# Line slope calculator 10x+y=50

**Straight line given by points A[4; 10] and B[5; 0]**

## Calculation:

**Slope-intercept form of line:**y = -10x+50

**Canonical form of the line equation:**10x+y-50 = 0

**Parametric form of the line equation:**

x = t+4

y = -10t+10 ; t ∈ R

**Slope:**m = -10

**Slope angle of line: φ =**-84°17'22″ = -1.4711 rad

**X intercept:**x

_{0}= 5

**Y intercept:**y

_{0}= q = 50

**Distance line from the origin:**d

_{0}= 4.9752

**The length of the segment AB: |AB| =**10.0499

**Vector: AB =**(1; -10)

**Normal vector: n =**(10; 1)

**Midpoint of the segment AB: M =**[4.5; 5]

**Perpendicular Bisector equation:**x-10y+45.5 = 0

**Vector OA = (4; 10) ; |OA| = 10.7703**

**Vector OB = (5; 0) ; |OB| = 5**

**Scalar product OA .OB = 20**

**Angle ∠ AOB = 68°11'55″ = 1.1903 rad**