# Line slope calculator 2x+3y=14

**Straight line given by points A[1; 4] and B[4; 2]**

## Calculation:

**Slope-intercept form of line:**y = -0.6667x+4.6667

**Canonical form of the line equation:**2x+3y-14 = 0

**Parametric form of the line equation:**

x = 3t+1

y = -2t+4 ; t ∈ R

**Slope:**m = -0.6667

**Slope angle of line: φ =**-33°41'24″ = -0.588 rad

**X intercept:**x

_{0}= 7

**Y intercept:**y

_{0}= q = 4.6667

**Distance line from the origin:**d

_{0}= 3.8829

**The length of the segment AB: |AB| =**3.6056

**Vector: AB =**(3; -2)

**Normal vector: n =**(2; 3)

**Midpoint of the segment AB: M =**[2.5; 3]

**Perpendicular Bisector equation:**3x-2y-1.5 = 0

**Vector OA = (1; 4) ; |OA| = 4.1231**

**Vector OB = (4; 2) ; |OB| = 4.4721**

**Scalar product OA .OB = 12**

**Angle ∠ AOB = 49°23'55″ = 0.8622 rad**